(9x^2-8)=(8x^2-2x)

Solution for (9x^2-8)=(8x^2-2x) equation:

(9x^2-8)=(8x^2-2x)

We move all terms to the left:

(9x^2-8)-((8x^2-2x))=0

We get rid of parentheses

9x^2-((8x^2-2x))-8=0


We calculate terms in parentheses: -((8x^2-2x)), so:

(8x^2-2x)

We get rid of parentheses

8x^2-2x

Back to the equation:

-(8x^2-2x)


We get rid of parentheses

9x^2-8x^2+2x-8=0

We add all the numbers together, and all the variables

x^2+2x-8=0

a = 1; b = 2; c = -8;
Δ = b2-4ac
Δ = 22-4·1·(-8)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-6}{2*1}=\frac{-8}{2}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+6}{2*1}=\frac{4}{2}
=2
$